b^2(3b+n)-n(3b+n)=

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Solution for b^2(3b+n)-n(3b+n)= equation: 


Simplifying
b2(3b + n) + -1n(3b + n) = 0
(3b * b2 + n * b2) + -1n(3b + n) = 0

Reorder the terms:
(b2n + 3b3) + -1n(3b + n) = 0
(b2n + 3b3) + -1n(3b + n) = 0
b2n + 3b3 + (3b * -1n + n * -1n) = 0
b2n + 3b3 + (-3bn + -1n2) = 0

Reorder the terms:
-3bn + b2n + 3b3 + -1n2 = 0

Solving
-3bn + b2n + 3b3 + -1n2 = 0

Solving for variable 'b'.

The solution to this equation could not be determined.

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